Topic: A math Problem (Experts needed)?**Question:**
What is the distance between (-14, -11) and (-20, -7) along the line connecting them?
Please explain me answer properly, and this is not a homework. I found this problem from a SSAT book and willing to know what could this be? I will just choose a good answer. First Best Answer will win it.

April 22, 2019 / By Abner

The X distance is simply the difference between the first X coordinate and the second. -14 - (-20) = -14+20 = 6. The Y distance is the difference between the first Y coordinate and the second. -11 - (-7) = -11+7 = -4. Now you have a right triangle. The bottom edge is 6 units long, and the vertical edge is 4 units long. The negative doesn't matter, because we will square it in a moment. To find the true distance between both points, we should use the pythagorean theorem. a^2 + b^2 = c^2, where a and b are both lesser side lengths, and c is the length of the hypotenuse, which in this case is the distance between the points. 6^2 + (-4)^2 = c^2 36 + 16 = c^2 52 = c^2 sqrt(52) = c 7.2111 = c I hope I helped you with this concept! Good luck on your SATs!

👍 102 | 👎 7

Did you like the answer? To answer any question, it helps to read the question in full. Your last sentence is missing some vital words: which of the following is the number of people needed to treat for this new meningitis vaccine TO PREVENT 1 CASE OF MENINGITIS? The number of cases prevented by the 10,000 vaccinations over 5 years is 74 - 24 = 50 10,000 vaccinations over 5 years / 50 prevented cases over 5 years = 200. That is the number of people you need to vaccinate to prevent 1 case of meningitis in the *study population*. The fact that 850 cases per 100,000 is not the same ratio as 74 cases per 10,000 implies that the study population is not representative of the USA. In particular, we have no idea of what the vaccination rate was in the general population. Unfortunately, this means one can draw no conclusions as to the figure for the number needed to treat required for the whole US population.

I believe the answer is sqrt(52) or 2sqrt(13). Basically, you take the two points and create a right triangle using the absolute value of the difference between the x-axis values (-20- -14 = -6) and the absolute value of the difference between the y-axis values (-11- -7 = -4). These distances would be the a and b sides of the right triangle. The distance between the two points is the hypotenuse of the right triangle. It may help to grab some scratch paper and sketch a graph of these points. It may help you to visualize the triangle. Now using the Pythagorean Theorem (a^2 + b^2 = c^2) you can solve for the distance between the two points (or the line connecting them), which is c. 6^2 + 4^2 = c^2 36 + 16 = c^2 52 = c^2 sqrt(52) = c I hope this helps.

👍 30 | 👎 -1

Just use the distance formula. It's the root of the sum of the difference of the x's plus the difference in the y'2. delta x = 6. delta y = 4. 6^2 + 4^2 = 36 + 16 = 52. The distance between them is sqrt(52), or 2*sqrt(13). -John

👍 24 | 👎 -9

distance between (-14, -11) and (-20, -7) along the line connecting them is = sqrt{(--14+20)^2 + (--11+7)^2} = 7.2111

👍 18 | 👎 -17

The distance equation is sqrt((x1-x2)^2+(y1-y2)^2) so sqrt((-14 - -20)^2 + (-11 - -7)^2) sqrt(36+16) sqrt(52) =7.211

👍 12 | 👎 -25

distance formula = √[(x1-x2)^2 + (y1-y2)^2] calculating we get, =√[(-14+20)^2 + (-11+7)^2] =√[(6)^2 + (4)^2] =√[36+16] = √52 = 7.2111

👍 6 | 👎 -33

Area of the triangle = 1/2(base x height) = 0.5(3 x 4) = 6 Area of the top is 1/2 a circle. Area of a circle = π x radius squared Thus the area of this 1/2 circle is (π x radius squared)/2 = (3.14 x 1.5)/2 = 2.355 Then the total area will be 2.355 + 6 = 8.355 Now for the perimeter: The perimeter of the 2 sides of the triangle is 4.25 + 4.25 = 8.5 The circumference of a circle is found using the formula π x D But you only have 1/2 a circumference. So, 1/2 circumference will be (π x 3)/2 = (3.14 x 3)/2 = 4.71 Thus the total perimeter will be 8.5 + 4.71 = 13.21 Hope this helps your 5th grade brother. Let me know if you need more help. I'm on YM or by email.

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