Algebra 2 homework help!? Topic: Algebra 2 homework help!?
June 18, 2019 / By Arielle
Question: Hello guys! I'm working on my algebra homework and am stuck on this one part of this problem. Im working on solving Hyperbolas and im trying to find what is c. a=-4 b=2 C2=A2+B2 the two's behind the numbers are suppose to mean their squared not twos. C2= 16+4 C2 = 20 I know I need to break it down more than that but i'm not sure what to do now please help! Best Answers: Algebra 2 homework help!? Zebedee | 8 days ago
C^2 = 20 U needed to find one C not C^2 so, the power of 2 is changed to square root C = square root of 20
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Did you like the answer? Algebra 2 homework help!? Share with your friends Originally Answered: algebra homework help?
Ok. You forgot to add Michelle's coins into the mix for your first equation. It should be: x + (x+7) + (3x-12) = 75 Then we get: 5x = 80 x=16 Which means Michelle has 16 Tim has 16 + 7 = 23 Nancy has 3 * 16 - 12 = 48 - 12 = 36 For the second one, you didn't add in Paul's age correctly. x = Mark's age 2x= Oscar's age Now, Paul is 3 years older than Oscar. In terms of x that means: 2x + 3 = Paul's age. Now we have the sum of their ages is 33, so we should have: x + (2x) + (2x + 3) = 33 Then we get: 5x = 30 x=6 Which means Mark is 6 years old, Oscar is 2 * 6 = 12 years old and Paul is 2*6 + 3 = 12 + 3 = 15 years old. Hope this helps!! Sid
c² = 20 c = √20 = √(4 * 5) = √4√5 = 2√5 Tip: if you are on a PC, to make the ² symbol, hold down alt, type 0178 on number pad (with num lock on), then let go of alt. 0179 is ³, 251 is √, 241 is ±, 227 is π, 242 is ≥, etc. You can see more at http://usefulshortcuts.com/alt-codes/mat... . For Apple computers, you can hold down the Option key & type letters for some of these (like P for π), but most are found on the Pallette & can be copied, I’m not an Apple guy so you will have to figure out how to open that.
👍 110 | 👎 1 Ogden
After attempting to sparkling up project after project on yahooanswers, I actual think of maximum individuals dont study plenty if I provide them the solutions. Heres an exceedingly comparable project. merely fill in the values out of your individual project. (hint: you will could desire to apply the Quadratic formula on the top!) Goodluck!!! question: The hypotenuse of a captivating triangle has a length of 13 cm. The sum of the lengths of the two legs is 17 cm. locate the lengths of the legs. permit a = length of one leg permit b = length of alternative leg we are advised that: a + b = 10.23 --> b = 10.23 - b [a million] The hypotenuse is 8.312. From Pythagorus: a² + b² = 8.312²  replace [a million] into : a² + (8.312 - b)² = 169 This simplifies to: 2a² - 34a + a hundred and twenty = 0 Divide by applying 2: a² - 17a + 60 = 0 which factors: (a - 5)(a - 12) = 0 and has roots: a = 5, 12 replace into [a million] and get: b = 12, 5 The lengths of the legs are 5 and 12 cm.
👍 103 | 👎 -6 Laurie
i think you just need to square root c, so c= √(4*5)= √((2)2*5)= 2√5 = 4.4721... if you want the exact number. Note: √((2)2*5) the second number two is the square
👍 96 | 👎 -13 Originally Answered: Algebra homework help?
with interest compounded every year you had ,suppose P,then 500 = P(1+ 2.5/100)^4 =P(1.025)^4 =P*1.103812890625 P =500/1.103812890625 =452.97532239987741355337553317496 =\$453 you had \$453. with simple interest,suppose you had P,then 500 =P +(P*2.5*4)/100 =P +P/10 500 =11P/10 P = 5000/11 =454.54545454545454545454545454545 =\$455 you had \$455.

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