ALGEBRA 2 HOMEWORK QUESTION HELP!?
Topic: ALGEBRA 2 HOMEWORK QUESTION HELP!?
July 16, 2019 / By Brogan Question:
i have one problem that i dont know how to do for my algebra 2/trig homework.
If you could answer this question and try to EXPLAIN how how did it. Thanks in advance.
1.) The hypotenuse of a right triangle is 8.312 cm long. The sum of the lengths of the legs is 10.23 cm. Use a calculator to find the lengths of the legs.
Please and thanks.
Best Answers: ALGEBRA 2 HOMEWORK QUESTION HELP!?
Alison | 8 days ago
8.312^2 = x^2 + (10.32-x)^2
69.09 = x^2 + 106.5 - 20.64x + x^2
0 = 2x^2 - 20.64x + 37.41
0 = x^2 - 10.32x + 18.7
x = [10.32 +/- *sqrt(10.32^2 - 4(1)(18.7))] / [2x1]
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Originally Answered: Math homework help( Algebra) another question?
Since her total pay was $273 during the week, this equation is correct (6W (amount on weekdays) 8X amount on weekends))
This is the total number of hours she worked in total. Now it's a matter of substitution.
On the weekends, she worked for 10 and a half hours. Now with this information, sub it in to get the other one.
So, on the weekdays, she worked for a total of 31 and a half hours.
Now to check,
After trying to solve problem after problem on yahooanswers, I honestly think most people dont learn a lot if I give them the answers. Heres a VERY similar problem. Just fill in the values from your own problem. (Hint: you will need to use the Quadratic Formula at the end!) Goodluck!!!
QUESTION: The hypotenuse of a right triangle has a length of 13 cm. The sum of the lengths of the two legs is 17 cm. Find the lengths of the legs.
Let a = length of one leg
Let b = length of other leg
We are told that: a + b = 10.23 --> b = 10.23 - b 
The hypotenuse is 8.312.
From Pythagorus: a² + b² = 8.312² 
Substitute  into : a² + (8.312 - b)² = 169
This simplifies to: 2a² - 34a + 120 = 0
Divide by 2: a² - 17a + 60 = 0
which factors: (a - 5)(a - 12) = 0
and has roots: a = 5, 12
Substitute into  and get: b = 12, 5
The lengths of the legs are 5 and 12 cm.
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Trey, give me a moment while I grab my abacus, he-he. Just kidding. This is a tricky one. You must've pulled a prank on your teacher to have something like this assigned. Well if you have it you have it, so ...
You know that the legs, a and b, sum to 10.23, so
a + b = 10.23.
You also know that a^2 + b^2 = 8.312^2 since it's a right triangle. Two equations, two unknowns, have at it son.
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isn't that 10.23 divided by 2? sine its the sum of the two legs i'm thinking you need to divide the sum by 2 to get the two lengths of the legs. 10.23 divided by 2 is 5.115 you can round.
Pothygreum Therum is A2+B2=C2
(the 2's are exponents)
hope this helps.
👍 86 | 👎 -10
[first, for the sake of clarity, switch f(x) with y] y=5x+4 [then, because this is how you find inverses, switch the (x)s and the (y)s] x=5y+4 [now solve for, or "isolate" y] x-4=5y (x-4)/5=y [so there's your answer, but I think inverse notation looks like this] f^-1(x)=(x-4)/5 [alternatively,] f^-1(x)=x/5+0.8 [or] f^-1(x)=x/5+4/5
👍 79 | 👎 -16
Originally Answered: Pre- Algebra homework question. 30 points?
Isolate the variable on one side.
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Multiply both sides by the reciprocal of the fraction.
y = 84
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