Algebra Homework?!? Exponential growth and decay?

Algebra Homework?!? Exponential growth and decay? Topic: Algebra Homework?!? Exponential growth and decay?
July 16, 2019 / By Suzette
Question: I need so much help with this. Please help? Explain how to identify equations as exponential growth, exponential decay, linear growth or linear decay. Help with these problems: y=3s+1 6x+5y=30 y=(3/4)^3 y=2x
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Best Answers: Algebra Homework?!? Exponential growth and decay?

Ravenna Ravenna | 3 days ago
y = 3s + 1 (linear) 6x + 5y = 30 (linear) y = (3/4)^3 (horizontal line) y = 2x (linear)
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Ravenna Originally Answered: I need help with Exponential Decay?
The problem states, this material decays at the rate of 2% per year. That means, if you begin with 100 grams, after a year, you have: 100 * 0.98 = 98 grams After another year, you have: 98 * 0.98 = 96.04 After another year, you have: 96.04 * 0.98 = 94.12 Don't get hung up on a word "decay". It simply means "loss." If you have 100 and lose 2, you have 98 left.

Merilyn Merilyn
These are all equations for a line on a graph or coordinate plane . Exponential growth is meaning that the values on the line would be steadily increasing . For example, money . Say you own a business and want to know how much money you have been making , or losing over the course of one month . A lot of times it is not going to be a consistent increase or decrease , but exponential growth means that it is exactly steady in the rate of growth . So these equations .. Are they steadily increasing in their values , or decreasing? The first one is gradually increasing by exponential growth . Because it gives you 3s Plus one every time , so it is growning exponentially by one. The second is linear growth The third is exponential decay . And the fourth is linear growth ... Hope I helped I tried to explain as best I could.
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Leonore Leonore
The equation could desire to be y = 35 (a million + 0.0.5)^x which turns into y = 35 (a million.0.5) ^x and y = a hundred and fifteen (a million - 0.0125) ^x which turns into y = a hundred and fifteen (0.9875)^x The numbers in parentheses are consistently the two a million minus the % (as a decimal) or a million plus the %, reckoning on no count if it fairly is a decrease or advance. It seems such as you have got forgotten to alter the % to a decimal first.
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Jordon Jordon
I dont know how to answer these questions but hotmath.com helps a lot :p just find your book and type in the page and click the #
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Jordon Originally Answered: exponential and logarithmic functions
Hi, Try to get the same base on each side, then set exponents equal to each other and solve. (1/2)^(1-x) = 4 (2^-1)^(1-x) = 2^2 (2^(-1(1-x)) = 2^2 Since bases are the same, set exponents equal to each other. (-1(1-x)) = 2 -1 + x = 2 x = 3 <==ANSWER 4^x - 2^x = 0 2^2x - 2^x = 0 2^2x = 2^x Since bases are the same, set exponents equal to each other. 2x = x x = 0 <==ANSWER (e^4)^x * e^x^2 = e^12 e^4x * e^x^2 = e^12 e^(4x + x²) = e^12 Since bases are the same, set exponents equal to each other. 4x + x² = 12 x² + 4x = 12 x² + 4x - 12 = 0 (x + 6)(x - 2) = 0 x = -6 or x = 2 <==ANSWER if 2^x = 3 then 4^-x = ??? 4^-x = (2²)^-x = 2^(-2x) = (2^x)^-2 Replace 2^x with 3 (2^x)^-2 = (3)^-2 = 1/3² = 1/9 <==ANSWER if 5^-x = 3 then 5^3x = ??? 5^3x = (5^-x)^-3 Replace 5^-x with 3 (5^-x)^-3 = (3)^-3 = 1/3³ = 1/27 <==ANSWER I hope that helps!! :-)
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