can someone plz help me with my algebra homework?

can someone plz help me with my algebra homework? Topic: can someone plz help me with my algebra homework?
June 18, 2019 / By Annabelle
Question: these are the problems below...i just dont know what to do c(c+7)=0 (x-9)(3x+5)=0 a squared -a=6 thank you so much in advance!! thank you so much everybody for explaining.... coming back from winter break is brutel when remebering algebra so thanks again!
Advertisement
Best Answer

Best Answers: can someone plz help me with my algebra homework?

Winthrop Winthrop | 8 days ago
I don't know how to express this as an equation, but the last one a=3. The backwards way to solve it is you take the squares of small numbers, 2 squared is four, that's too small. 3 squared is 9. You subtract 9-3 = 6. 4 squared is 16, 16-4= 12, so that's too much.
👍 184 | 👎 8
Did you like the answer? can someone plz help me with my algebra homework? Share with your friends
Winthrop Originally Answered: I need help with my algebra 1 homework please?
2l = w 2l + 2w = p p = 42 2l + 2(2l) = 42 2l + 4l = 42 6l = 42 l = 7 w = 14 the dimensions are 14 x 7 x + (1.5x) = 850 2.5x = 850 x = 340 one friend pays 340 and the other 510 15 + 2.05g = 2.35g 15 = .30g g = 50 gallons need to be bought in a month 3 + 5.5h = 7h 3 = 1.5h h = 2 hours for him to catch up

Shamus Shamus
These look like factoring: For the first two, you set each equal to 0... c in the first one is like c+0, so c+ 0 = 0. c = 0. c+7 = 0, so c = -7 So your two answers are -7 and 0 The second you have x-9 =0 so x = 9 and 3x+5 = 0 so x = (-5/3) because you subtract 5 by both sides and then divide by 3 to get x alone. So your two answers are 9 and -5/3 a sqaured - a = 6, you will need to move the 6 to the other side by subtracting. You need the equation to equal 0. a squared - a -6 = 0. Now you will need to factor that into two binomials (a-3)(a+2) = 0. now a-3 = 0 so a = 3 and a+2 = 0 so a = -2 Your two answers are 3 and -2
👍 70 | 👎 1

Newton Newton
c(c+ 7 ) = 0 use the zero product property either c= o or c+7 = 0 c = 0 or c = -7 (x-9)(3x+5)=0 use zero product property again x -9 = 0 or 3x + 5 =0 x = 9 or 3x = -5 x = 9 or x = -5/3 a^2 - a = 6 a^2 - a - 6 = 0 (a -3)(a+2) = 0 a - 3 = 0 or a+2=0 a = 3 or a = -2 hope that helps!
👍 63 | 👎 -6

Kirk Kirk
c(c+7)=0 C=0 and c=-7 x-9=0 and 3x+5 =0 x=9 and 3x=-5 x=9 and x =-5/3 A squared -a =6 A squared -a -6=0 (a+2)(a-3)=0 a=-2 and a=3
👍 56 | 👎 -13

Hyram Hyram
1 c(c+7)=0 you have to multiply c+7 by c so you get c^2 +7c=0 depending on what the homework question is will determine what you have to do next. #2 basically you do this: x * 3x =3x^2 x * 5 = 5x -9 * 3x = -27x -9 * 5 = -45 9add liked terms and you get: 3x^2 - 22x -45 (i don't know if you have to foil it, but this is simplest form) #3 -a=6 finding the square of -a would be i(square sign)a =2(square sign)3 i can't make the sign here but here is a link to what it is sappost to look like. just put it where i said, and take out the x. http://etc.usf.edu/clipart/41700/41750/FC_SqRootX_41750_lg.gif hope this helps
👍 49 | 👎 -20

Hyram Originally Answered: Algebra Homework Help?
1: I'd multiply the second equation by -2: -2W + 2U = -120 I'd then add i) and ii) together: W = -108 I'd then find U by inserting that value for W in any of the two equations. 2: Here, I'd multiply the first equation by 3 and the second by -2. I'd then do the same as I did under 1, above. Your factoring is clearly wrong. (D + 1)(D - 6) = D^2 - 6D + D - 6 = D^2 - 5D - 6 . You seem to have a sign error somewhere. The second factoring is correct. By inspection, one can then see that the zeroes for the equation is J = -25 and J = -1.
Advertisement

If you have your own answer to the question can someone plz help me with my algebra homework?, then you can write your own version, using the form below for an extended answer.