Topic: can someone plz help me with my algebra homework?**Question:**
these are the problems below...i just dont know what to do
c(c+7)=0
(x-9)(3x+5)=0
a squared -a=6
thank you so much in advance!!
thank you so much everybody for explaining.... coming back from winter break is brutel when remebering algebra so thanks again!

June 18, 2019 / By Annabelle

I don't know how to express this as an equation, but the last one a=3. The backwards way to solve it is you take the squares of small numbers, 2 squared is four, that's too small. 3 squared is 9. You subtract 9-3 = 6. 4 squared is 16, 16-4= 12, so that's too much.

👍 184 | 👎 8

Did you like the answer? 2l = w 2l + 2w = p p = 42 2l + 2(2l) = 42 2l + 4l = 42 6l = 42 l = 7 w = 14 the dimensions are 14 x 7 x + (1.5x) = 850 2.5x = 850 x = 340 one friend pays 340 and the other 510 15 + 2.05g = 2.35g 15 = .30g g = 50 gallons need to be bought in a month 3 + 5.5h = 7h 3 = 1.5h h = 2 hours for him to catch up

These look like factoring: For the first two, you set each equal to 0... c in the first one is like c+0, so c+ 0 = 0. c = 0. c+7 = 0, so c = -7 So your two answers are -7 and 0 The second you have x-9 =0 so x = 9 and 3x+5 = 0 so x = (-5/3) because you subtract 5 by both sides and then divide by 3 to get x alone. So your two answers are 9 and -5/3 a sqaured - a = 6, you will need to move the 6 to the other side by subtracting. You need the equation to equal 0. a squared - a -6 = 0. Now you will need to factor that into two binomials (a-3)(a+2) = 0. now a-3 = 0 so a = 3 and a+2 = 0 so a = -2 Your two answers are 3 and -2

👍 70 | 👎 1

c(c+ 7 ) = 0 use the zero product property either c= o or c+7 = 0 c = 0 or c = -7 (x-9)(3x+5)=0 use zero product property again x -9 = 0 or 3x + 5 =0 x = 9 or 3x = -5 x = 9 or x = -5/3 a^2 - a = 6 a^2 - a - 6 = 0 (a -3)(a+2) = 0 a - 3 = 0 or a+2=0 a = 3 or a = -2 hope that helps!

👍 63 | 👎 -6

c(c+7)=0 C=0 and c=-7 x-9=0 and 3x+5 =0 x=9 and 3x=-5 x=9 and x =-5/3 A squared -a =6 A squared -a -6=0 (a+2)(a-3)=0 a=-2 and a=3

👍 56 | 👎 -13

1 c(c+7)=0 you have to multiply c+7 by c so you get c^2 +7c=0 depending on what the homework question is will determine what you have to do next. #2 basically you do this: x * 3x =3x^2 x * 5 = 5x -9 * 3x = -27x -9 * 5 = -45 9add liked terms and you get: 3x^2 - 22x -45 (i don't know if you have to foil it, but this is simplest form) #3 -a=6 finding the square of -a would be i(square sign)a =2(square sign)3 i can't make the sign here but here is a link to what it is sappost to look like. just put it where i said, and take out the x. http://etc.usf.edu/clipart/41700/41750/FC_SqRootX_41750_lg.gif hope this helps

👍 49 | 👎 -20

1: I'd multiply the second equation by -2: -2W + 2U = -120 I'd then add i) and ii) together: W = -108 I'd then find U by inserting that value for W in any of the two equations. 2: Here, I'd multiply the first equation by 3 and the second by -2. I'd then do the same as I did under 1, above. Your factoring is clearly wrong. (D + 1)(D - 6) = D^2 - 6D + D - 6 = D^2 - 5D - 6 . You seem to have a sign error somewhere. The second factoring is correct. By inspection, one can then see that the zeroes for the equation is J = -25 and J = -1.

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