Can you help me with my Algebra 2 homework? Topic: Can you help me with my Algebra 2 homework?
June 19, 2019 / By Sommer
Question: There are 9 males and 15 females in a math class. A committee of 4 students is randomly selected to plan a party. What is the probability that the committee consists of 2 males and 2 females? An explanation would be helpful. Also, I have a test tomorrow on permutations, combinations, and probability. I feel like I don't know the material very well even though I've done all the work. Any pointers or tricks with this type of math? sorry, i forgot to add the possible answers because the worksheet it mulitple choice so here are the possible answers a. 0.003 b. 0.010 c. 0.167 d. 0.356 Best Answers: Can you help me with my Algebra 2 homework? Pollyanna | 2 days ago
Probablity of one male =9/(9+15)=0.375 Because now we have one less male, so the probability of second male is: 8/(8+15)=0.348 (two males are out now) Probablity of third person is female =15/(7+15)=0.6818 (three, two males and one female are out now), so probablity of the forth person is female 14/(7+14)=0.6667 Probablity of 1st male, 2nd male, 3rd female and 4th female is P(1st male) * P(2nd male) * P(3rd female) * P(4th female) = 0.375 *0.348*0.6818*0.6667= 0.0593 or 5.93% now you could take the question further: what is the probability of all male panel? (total number is 4) =P(1st male) * P(2nd male) * P(3rd male) * P(4th male) =(9/24) * (8/23) * (7/22) * (6/21) = = 0.375 * 0.348* 0.3182 *0.2857 = 0.012 or 1.2% (see how low the chance is) Read this about Permutation & combinations: http://en.wikipedia.org/wiki/Permutation
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Did you like the answer? Can you help me with my Algebra 2 homework? Share with your friends Originally Answered: Algebra 2 homework help!?
All you're doing is getting the variable you want by itself, isolating it. You do this by performing additions/subtractions and multiplications/divisions to each side of the equation. Just take them slow, and do one number or letter at a time like this: 2) 2x + 75 = 102 - x x + 2x + 75 = 102 - x + x 3x + 75 = 102 3x + 75 - 75 = 102 - 75 3x = 27 3x / 3 = 27 / 3 x = 9 4) 3pq/r = 12 r * 3pq/r = 12 * r 3pq = 12r 3pq / 3 = 12r / 3 pq = 4r pq / q = 4r / q p = 4r/q Originally Answered: Algebra 2 homework help!?
The directions just say Solve each equation. If you could answer any of these it would be a great help! Thanks 1. 4n + 20 = 53 - 2n 4n + 2n = 53 – 20 6n = 33 n = 33/6 = 11/2 2. 2x + 75 = 102 – x 2x + x = 102 – 75 3x = 27 x = 27/3 = 9 The directions for the next one says Solve each equation or formula for the specified variable. Oh btw. n/m means like n over m. Just to make that clear lol 3. s/2t = 10, solve for t s/10 = 2t t = s/20 4. 3pq/r = 12, solve for p 3pq = 12r p = 12r/3q = 4r/q 5. 3(2j - k) = 108, solve for j 6j – 3k = 108 6j = 3k + 108 j = (1/2)k + 18 6. 3.5s – 42 = 14t, solve for s 3.5s = 14t + 42 s = (14t + 42)/3.5 = 4t + 12 Maude
When solving for the probability of something happening, first find the number of possible ways that you can have the specific event happen. You then take that number, and divide it by the total number of ways that things can play out. So, to solve your problem, (9 x 8 x 15 x 14) / (24 x 23 x 22 x 21). This will give you .0593, which translates into a 5.93% of having 2 males and 2 females selected. If you aren't comfortable with the material, I recommend that you go in early for help if you can.
👍 30 | 👎 -6 Lashonda
smart-aleck answer. 100%, just put all the guys' names in one jar and all the girls' names in another and pull two names out of each jar. Sorry, I can't wrap my head around the real answer.
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x + y = 32, x = 32 - y x = 5y + 2 32 - y = 5y + 2 30 = 6y y = 5 x = 32 - 5 = 27

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