Topic: Can you help me with this algebra problem?**Question:**
I would like some help with this problem. It is not homework or anything, I am just doing it for fun. I would appreciate it if you could give me the answers and show your work( you don't have to show work but it will help me if you do). Heres the link
http://mathbits.com/caching/a16875.html
Thanks in advance!

July 16, 2019 / By Shantel

1st one is simple factoring (x+20)(x-15), choice 3 2nd one also factoring (5x+1)(x-2), choice 3 3rd one has a b in both terms so factor that out b(a^2-25) now you have a difference of squares b(a+5)(a-5), choice 1 Bonus Answer: i don't know if you want it but ill give it to you anyway sum is 7, square root of 49 is 7, 7^4 is 2401 so answer should be 2401x7=16807 and i tried it it works :)

👍 110 | 👎 1

Did you like the answer? take (93 + 87 + 82 + 86 + x + (x+4) ) / 6 = 87 and solve it for x. Note that it doesn't matter if you use x+4 or x-4... the results will be the same. If you use x+4, x will represent the lower score, and if you use x-4 the x will give you the higher. Given the choice of + or - to work with, I typically choose +.

Let the scores of Angela in six tests respectively be: 93,87,82,86, x and x-4.So average = [93+87+82+86+x+x-4]/6 = 87 or [93+87+82+86+x+x-4] = 87*6 = 522 or 344 + 2x = 522 or 2x = 178 or x = 89 So Angela scored 89 on fifth test and 85 on sixth test.

the answers are: 1. 3 2. 3 3 .1 (these are numbers for the correct answers - all found by factoring) sum them = 7 now square root 49 = 7 7^4 x 7 = 7^5 = 16807

👍 40 | 👎 -4

1. (x+20)(x-15) 20x-15=-300 20-15=5 2.(5x+1)(x-2) -2x5=-10+1=-9 3. b(a^2-25) b(a-5)(a+5) I dont know how to show my work it is just guessing and checking till it works.

👍 40 | 👎 -9

5 - 4|2 - 3t| > 21 -4|2 - 3t| > 16 |2 - 3t| < -4 There is no solution because an absolute value cannot be negative.

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