Topic: Help with integer exponents, please!?**Question:**
Trying to complete yet another Algebra homework assignment, and I am stuck on 4 problems. Would someone mind helping me solve the problems, and also explain why you did what you did? THANK YOU for your help! "Answers" has been a blessing when it comes to my Algebra homework!!! :o)
1. p^-5q^-4 / 9r^-3
2. (p^-4q / r^-3)^-3
3. (m^8n^-4)^2 / m^-2n^5
4. (wz^-5 / w^-3z)^-2
THANK YOU AGAIN TO ALL YOU MATH WHIZZES!!! :o)

July 16, 2019 / By Sabryna

1. p^-5q^-4/qr-3 = r^3/9p^5q^4 2. (p^-4q/r^-3)^-3 = (r^3q/p^4)^-3 = (P^4/r^3q)^3 = p^12/r^9q^3 3. (m^8n^-4)^2/m^-2n^5 = m^16n^-8/m^-2n^5 = m^16m^2/n^5n^8 = m^8/n^13 4. (wz^-5/w^-3z)^{-2} = (ww^3/zz^5)^{-2} = (w^4/z^6)^{-2} = z^6/w^4)^2 = z^12/w^8

👍 194 | 👎 3

Did you like the answer? 1. p^-5q^-4/qr-3 = r^3/9p^5q^4 2. (p^-4q/r^-3)^-3 = (r^3q/p^4)^-3 = (P^4/r^3q)^3 = p^12/r^9q^3 3. (m^8n^-4)^2/m^-2n^5 = m^16n^-8/m^-2n^5 = m^16m^2/n^5n^8 = m^8/n^13 4. (wz^-5/w^-3z)^{-2} = (ww^3/zz^5)^{-2} = (w^4/z^6)^{-2} = z^6/w^4)^2 = z^12/w^8

hi, it relatively is incredibly shopper-friendly. There are 2 themes first one is base and 2nd one is exponent. think of you have a form 3^2. Then 3 is the backside and a couple of is the exponent. on the behalf of there 2. There are some properties- a million. If the bases are comparable and are in multiplication, then skill/exponent are greater. as an party- a^3 *a^2=a^5 2. If there is skill on skill, then powers get greater ideal. as an party- (a^3 )^2= a^6. 3. If the bases are diverse, powers are comparable, then you certainly ought to freshen up it relatively. 4. If the skill is 0 then the top result would be one continuously in spite of the cost of base is taken.

hi, it relatively is incredibly shopper-friendly. There are 2 themes first one is base and 2nd one is exponent. think of you have a form 3^2. Then 3 is the backside and a couple of is the exponent. on the behalf of there 2. There are some properties- a million. If the bases are comparable and are in multiplication, then skill/exponent are greater. as an party- a^3 *a^2=a^5 2. If there is skill on skill, then powers get greater ideal. as an party- (a^3 )^2= a^6. 3. If the bases are diverse, powers are comparable, then you certainly ought to freshen up it relatively. 4. If the skill is 0 then the top result would be one continuously in spite of the cost of base is taken.

👍 80 | 👎 -3

1.) p^-5q^-4/qr-3 = r^3/9p^5q4 2.) (p^-4q/r^-3)^-3 = (r^3q/p^4)^-3 = (P^4/r^3q)3 = p^12/r^9q^3 3.) (m^8n^-4)^2/m^-2n^5 = m^16n^-8/m^-2n^5 = m^16m^2/n^5n^8 = m^8/n^13 4.) (wz^-5/w^-3z)^-2 = (ww^3/zz^5)^-2 = (w^4/z^6)^-2 = z^6/w^4)^2 = z^12/w^8

👍 78 | 👎 -9

An integer is another word for a whole number (without decimal places) -1207 is an integer, as it is a whole number.

If you have your own answer to the question Help with integer exponents, please!?, then you can write your own version, using the form below for an extended answer.
/**
* RECOMMENDED CONFIGURATION VARIABLES: EDIT AND UNCOMMENT THE SECTION BELOW TO INSERT DYNAMIC VALUES FROM YOUR PLATFORM OR CMS.
* LEARN WHY DEFINING THESE VARIABLES IS IMPORTANT: https://disqus.com/admin/universalcode/#configuration-variables*/
/*
var disqus_config = function () {
this.page.url = PAGE_URL; // Replace PAGE_URL with your page's canonical URL variable
this.page.identifier = PAGE_IDENTIFIER; // Replace PAGE_IDENTIFIER with your page's unique identifier variable
};
*/
(function() { // DON'T EDIT BELOW THIS LINE
var d = document, s = d.createElement('script');
s.src = 'https://help-study.disqus.com/embed.js';
s.setAttribute('data-timestamp', +new Date());
(d.head || d.body).appendChild(s);
})();
Please enable JavaScript to view the comments powered by Disqus.

Copyright 2019. All rights reserved | Read Questions Online