# Help with integer exponents, please!?

Topic: Help with integer exponents, please!?
July 16, 2019 / By Sabryna
Question: Trying to complete yet another Algebra homework assignment, and I am stuck on 4 problems. Would someone mind helping me solve the problems, and also explain why you did what you did? THANK YOU for your help! "Answers" has been a blessing when it comes to my Algebra homework!!! :o) 1. p^-5q^-4 / 9r^-3 2. (p^-4q / r^-3)^-3 3. (m^8n^-4)^2 / m^-2n^5 4. (wz^-5 / w^-3z)^-2 THANK YOU AGAIN TO ALL YOU MATH WHIZZES!!! :o)

Nettie | 3 days ago
1. p^-5q^-4/qr-3 = r^3/9p^5q^4 2. (p^-4q/r^-3)^-3 = (r^3q/p^4)^-3 = (P^4/r^3q)^3 = p^12/r^9q^3 3. (m^8n^-4)^2/m^-2n^5 = m^16n^-8/m^-2n^5 = m^16m^2/n^5n^8 = m^8/n^13 4. (wz^-5/w^-3z)^{-2} = (ww^3/zz^5)^{-2} = (w^4/z^6)^{-2} = z^6/w^4)^2 = z^12/w^8
👍 194 | 👎 3
1. p^-5q^-4/qr-3 = r^3/9p^5q^4 2. (p^-4q/r^-3)^-3 = (r^3q/p^4)^-3 = (P^4/r^3q)^3 = p^12/r^9q^3 3. (m^8n^-4)^2/m^-2n^5 = m^16n^-8/m^-2n^5 = m^16m^2/n^5n^8 = m^8/n^13 4. (wz^-5/w^-3z)^{-2} = (ww^3/zz^5)^{-2} = (w^4/z^6)^{-2} = z^6/w^4)^2 = z^12/w^8
hi, it relatively is incredibly shopper-friendly. There are 2 themes first one is base and 2nd one is exponent. think of you have a form 3^2. Then 3 is the backside and a couple of is the exponent. on the behalf of there 2. There are some properties- a million. If the bases are comparable and are in multiplication, then skill/exponent are greater. as an party- a^3 *a^2=a^5 2. If there is skill on skill, then powers get greater ideal. as an party- (a^3 )^2= a^6. 3. If the bases are diverse, powers are comparable, then you certainly ought to freshen up it relatively. 4. If the skill is 0 then the top result would be one continuously in spite of the cost of base is taken.

Lunet
hi, it relatively is incredibly shopper-friendly. There are 2 themes first one is base and 2nd one is exponent. think of you have a form 3^2. Then 3 is the backside and a couple of is the exponent. on the behalf of there 2. There are some properties- a million. If the bases are comparable and are in multiplication, then skill/exponent are greater. as an party- a^3 *a^2=a^5 2. If there is skill on skill, then powers get greater ideal. as an party- (a^3 )^2= a^6. 3. If the bases are diverse, powers are comparable, then you certainly ought to freshen up it relatively. 4. If the skill is 0 then the top result would be one continuously in spite of the cost of base is taken.
👍 80 | 👎 -3

Kaylee
1.) p^-5q^-4/qr-3 = r^3/9p^5q4 2.) (p^-4q/r^-3)^-3 = (r^3q/p^4)^-3 = (P^4/r^3q)3 = p^12/r^9q^3 3.) (m^8n^-4)^2/m^-2n^5 = m^16n^-8/m^-2n^5 = m^16m^2/n^5n^8 = m^8/n^13 4.) (wz^-5/w^-3z)^-2 = (ww^3/zz^5)^-2 = (w^4/z^6)^-2 = z^6/w^4)^2 = z^12/w^8
👍 78 | 👎 -9

Originally Answered: What is an Integer? Need help with some homework :)?
An integer is another word for a whole number (without decimal places) -1207 is an integer, as it is a whole number.

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