Please help me - more precalc homework?

Please help me - more precalc homework? Topic: Please help me - more precalc homework?
June 18, 2019 / By Austyn
Question: Trying to pass my precalc class with a decent understanding of the material please help, answer with explanation please :) 30. Compare the graph of the function with the graph of f(x) = √x to y = √-x 36. Compare the graph of the function with the graph of f(x) = |x| to y = |1/2x| 42. Specify the sequence of transformations that will yield the graph of the given function from the graph of the function f(x) = x3 to g(x) = -(x-4)^3 ...i cant really understand the terminology of these three, no clue what the question is even asking 45. Find the inverse of the function f. Use a graphing utility to graph both f and f-1 in the same viewing rectangle. Describe the relationship between the graphs. f(x) = x^2, x is greater than/equal to zero 46. Determine whether the function has an inverse. If it does, find its inverse. f(x) = (3x+4) / 5 48. Determine whether the function has an inverse. If it does, find its inverse. f(x) = x - 5^2 52. Determine whether the function has an inverse. If it does, find its inverse. f(x) = square root of (x-5)^2 72. Use the functions f(x) = 1/8x - 3 and g(x) = x3 to find the indicated value or function. (g^-1 o f^-1) (-3) 80. Use the functions f(x) = x+4 and g(x) = 2x-5 to find the specified function. (g o f)^-1
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Best Answers: Please help me - more precalc homework?

Abbygail Abbygail | 5 days ago
30) f(x) = √(x) ====> Domain [0 , ∞) f(x) = √(-x) ====> Domain (-∞ , 0] ========== 36) f(x) = |x| =====> Domain (-∞ , ∞) y = | (1/2) * x | ====> Domain (-∞ , ∞) f(x) = |x| =====> the factor of the variable x which is 1, remains the same y = | (1/2) * x | ====> stretches away from the y-axis. ========== 42) f(x) = x^3 <===== parent function. g(x) = -(x-4)^3 ====> reflecting across the x-axis and shifted to the right 4 units. shifted to the right 4 units because of the -4 reflecting across the x-axis because of the negative outside the parenthesis, =========== 45) f(x) = x^2 y = x^2 =====> now, switch variable x = y^2 ====> solve for y +/- √(x) = y = f^-1(x) <===== f(x) = x y = x ===> switch x = y = f^-1(x) <====== http://www.wolframalpha.com/input/?i=y+%... =========== 46) f(x) = (3x+4) / 5 ===> switch variable x = (3y + 4)/5 ====> solve for y 5x = 3y + 4 5x - 4 = 3y (5x - 4)/3 = y = f^-1(x) ========= 48) f(x) = x - 5^2 x = y - 5^2 x + 5^2 = y = f^-1(x) ========= 52) f(x) = √( (x-5)^2 ) x = √( (y-5)^2 ) x^2 = (y-5)^2 +/- √(x^2) = y-5 +/- x + 5 = y = f^-1(x) =========== 72) f(x) = (1/8)x - 3 x = (1/8)y - 3 x + 3 = (1/8)y 8x + 24 = y = f^-1(x) g(x) = x^3 x = y^3 (x)^(1/3) = y = g^-1(x) ( g o f )^-1(x) = g^-1(x) o f^-1(x) = g^-1( f^-1(x) ) g^-1( 8x + 24 ) ( 8x + 24 )^(1/3) ====> when x = -3 ( 8*-3 + 24 )^(1/3) ( -24 + 24 )^(1/3) 0 ============ 80) f(x) = x + 4 x = y + 4 x - 4 = y = f^-1(x) g(x) = 2x - 5 x = 2y - 5 x + 5 = 2y (x + 5)/2 = y = g^-1(x) ( g o f )^-1(x) = g^-1(x) o f^-1(x) = g^-1( f^-1(x) ) g^-1( f^-1(x) ) g^-1( x - 4 ) ( x - 4 + 5)/2 ) (x + 1)/2 ========= please e-mail me if u have a question.
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Abbygail Originally Answered: Please help me with my homework! It's reading homework, due tomorrow and I have no idea what to write!?
Hmmm. Say something like it's a reality check to realize that there are bigger things going on than what is just in your town. I mean think about it- there is all sorts of crazy stuff going on in outerspace. For all we now, there could be an asteroid coming down to kill us all as we speak. Reading an article like the one you read can be a real eye-opener to make others realize that science works in it's own crazy ways and it's very unpredictable.
Abbygail Originally Answered: Please help me with my homework! It's reading homework, due tomorrow and I have no idea what to write!?
you can say that to her face and probably she will laugh at your remark or give you a BIG F! anyway, just to be on the safe side, you can tell your teacher that you read the article because if makes you feel like life is short and that anything can happen to us in an instant. that we should not be wasting time and should enjoy each day as if it is our last...

Ste Ste
30. the difference is y=-sqrt(x) is the reflection of sqrt(x) over the x=axis. 36. the absolute value of x is strected by a factor of 1/2. 42. You'll reflect across the y-axis and move 4 units to the right. to find the inverse you replace your x with y and y with x and solve for y.
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Ozzie Ozzie
be careful ... you will lose suggestions while you're taking too many shortcuts: x^4 = sixteen x^4 - sixteen = 0 (x² - 4)(x² + 4) = 0 (x - 2)(x + 2)(x² + 4) = 0 x - 2 = 0 or x + 2 = 0 or x² + 4 = 0 x = 2 or x = -2 or x² = -4 Now for x² = -4 x² = 4i² x = ±2i so the suggestions are x = -2 or x = 2 or x = -2i or x = 2i
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Ozzie Originally Answered: I can't do homework without snacking. Any ideas for healthy homework snacks?
I was always hungry when I got home from school, so the first thing I'd do is make myself a tray of veggies or fruits with cheese. You can really have a variety, pick and choose whatever you want. My favorites were always celery with peanut butter, apples with cheddar cheese, broccoli, grapes, or strawberries with raw honey.
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